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Mathematics 13 Online
OpenStudy (anonymous):

solve

OpenStudy (anonymous):

\[\sqrt{12+4x \ge6}\]

OpenStudy (anonymous):

haha, I got this :P

OpenStudy (anonymous):

hold on...

OpenStudy (anonymous):

o.o im not getting anything....

OpenStudy (jdoe0001):

\(\bf \sqrt{12+4x}\ge 6\implies \begin{cases} +(\sqrt{12+4x})\ge 6\\ \quad \\ \bf -(\sqrt{12+4x})\ge 6 \end{cases}\)

OpenStudy (jdoe0001):

ohh wait... smokes, nevermind that

OpenStudy (anonymous):

thank yall!

OpenStudy (anonymous):

okayy lol

OpenStudy (jdoe0001):

for a sec I thought it was hehe absolute value.. ok well hmm

OpenStudy (anonymous):

plus, the ">=" is under the square root symbol...

OpenStudy (anonymous):

its not supossed to be lol sorry

OpenStudy (jdoe0001):

\(\bf \sqrt{12+4x}\ge 6 \qquad \textit{square both sides}\\ \quad \\ 12+4x\ge 6^2\implies 4x\ge \cfrac{36}{12} \)

OpenStudy (anonymous):

LOL THATS WHY I'M NOT GETTING ANYTHING. x = >=6

OpenStudy (jdoe0001):

so you'd solve it more or less in the same way you'd any linear equation

OpenStudy (anonymous):

thank you!

OpenStudy (anonymous):

|dw:1382746929724:dw|

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