Question

Two cards are randomly chosen from an ordinary deck of 52 cards, without replacement. Determine the probability of each event. (Enter each probability as a fraction.)
(a) The first card is a face card.


(b) The second card is a face card, given the first card is an ace.

Answer 1

how many face cards are in an ordinary deck?

Answer 2

16 or 18

Answer 3

depending on the author: jkqa, or jkq per suit, so 16 or 12

since im not the author of your material ... what would you say are the possible probabilities out of 52 cards?

Answer 4

16/52?

Answer 5

and of course the second one doesnt help clarify the face card issue :) im guessing that aces are faces in this setup .... just a hunch since they use it in the second part

Answer 6

16/52 is good, or 12/52 would have been workable by some

Answer 7

now the second question assumes that you have already drawn an ace (which may be a face card); how many face cards are left to choose?

Answer 8

11

Answer 9

so 11/52, correct?

Answer 10

no replacement, 51 cards remain:

15/51 if ace is a face, or 16/51 if not

Answer 11

or 12/51?

Answer 12

if we spread out 52 cards and remove 1 ace ... that leaves us with 51 cards to work with

if aces area faces, then we have 15/51 probability of choosing a face

if aces are not faces, then yeah, 12/51 would do it :)

Answer 13

ok, thanks!

Answer 14

:) youre welcome