C6H12O6+6O2→6CO2+6H2O

a)If 3.8 kcal is released by combustion of each gram of glucose, how many kilocalories are released by the combustion of 1.69mol of glucose?

*I calculated 180g/mole to be the Molecular weight of Glucose,
I keep on getting 1157.116 kcal's but it says my answer is close but it's rounded off incorrectly.
I did it like a million times and I keep on getting the same thing! ):
-Please help!!!! ):

Question

C6H12O6+6O2→6CO2+6H2O

a)If 3.8 kcal is released by combustion of each gram of glucose, how many kilocalories are released by the combustion of 1.69mol of glucose?

*I calculated 180g/mole to be the Molecular weight of Glucose, 
I keep on getting 1157.116 kcal's but it says my answer is close but it's rounded off incorrectly.
I did it like a million times and I keep on getting the same thing! ):
-Please help!!!! ):

anonymous · Answer

1.69mol * (180g/1) * 3.8kcal/g = 4800 with correct sigfigs

anonymous · Answer

1.69mol * (180g/1) * 3.8kcal/g = 4800kcal  with correct sigfigs

anonymous · Answer

It says it's wrong, thanks though. ):

anonymous · Answer

And actually, your equation equaled to 1155.96 btw.(: Thanks for trying!

doc.brown · Answer

2 sig figs from 3.8
=1200