Question

Find dy/dx: y= (sin(x))^-5 - (cos(x))^3

Answer 1

We have:
\[y=\sin^5(x)-\cos^3(x)\]
So then we need to apply the chain rule which is: \(\frac{d}{dx}(f\circ g)(x)=f'[g(x)]g'(x)\)
We obtain:
\[\eqalign{
\frac{dy}{dx}&=5\sin^4(x)\cos(x)-3\cos^2(x)(-\sin(x)) \\
&=5\sin^4(x)\cos(x)+3\cos^2(x)\sin(x) \\

}\]

Answer 2

Oh I get it now thanks :)

Answer 3

Anytime :)