Question

If a man runs 'M' miles in 'T' hours, his speed is
A. M/T
B. M + T
C. M - T
D. MT

Answer 1

If he runs 10 miles in 10 hours then his speed would be 1 mile per hour. so 10/10 or M/T

Answer 2

Using "1 mile per hour", you can find the speed? So is there a formula that you can prove pied?

Answer 3

*provide

Answer 4

I was just using that as an example, but you can use the formula speed=M/T for any numbers. 20 miles in 2 hours; apply the formula s=m/t; s=20/2; s=10mph

Answer 5

Can you help me with another one? I have the answer but I just would like to know if I am correct. :)

Answer 6

ok

Answer 7

In how much less time does a runner who finishes a marathon in 2 hours 12 minutes 38 seconds complete the race than a runner who finishes in 3 hours 2 minutes 24 seconds?

Answer 8

A. 48 min. 56 sec.
B. 49 min. 46 sec.
C. 1 hr. 51 min. 22 sec.
D. 1 hr. 26 min. 12 sec.

I got B.

Answer 9

So you would just subtract the first runners time from the second runners time:
3:02:24
-2:12:38
----------
0:49:46

Answer 10

you just have to remember when you carry the minute over to the seconds that you are adding 60. Same goes for the hours the minutes.

Answer 11

CB=30 miles
BA=40 miles

Two drivers begin at point C simultaneously. One drives from C to B to A. The other drives directly to A at 50 mph. How fast must the first person drive to get to A first?

Answer 12

Is this a triangle or a straight line?

Answer 13

Triangle

Answer 14

gotcha. A right triangle I assume?

Answer 15

Yes

Answer 16

Like this?

Answer 17

Switch the places of the numbers.

Answer 18

Ok. So using Pythagorean theorem a^2+b^2=c^2 we know that the hypotenuse is 50 miles ((900+1600=2500) sqrt of 2500 is 50) so if driver 2 is driving 50 miles at 50 miles per hour it will take him one hour to get there. Driver 1 has to drive 30 miles + 40 miles in 1 hour, so he has to drive 70 miles per hour to get there at the same time.

Answer 19

so to get there first he must drive >70mph

Answer 20

How did you get more than 70 mph?

Answer 21

well he has to cover the 30 miles from c to b, and then 40 miles from b to a. So he has to drive 70 miles. And if he only has 1 hour to drive 70 miles he has to drive faster than 70mph to get there first

Answer 22

Your a math wiz!

Answer 23

Lol. I'm working on my masters to be a math teacher

Answer 24

Event A occurs every 4 years, event B every 11 years, and event C every 33 years. IF they last occurred together in 1950, when will they next occur simultaneously?

Answer 25

(F) 3,402
(G) 1,983
(H) 2,082
(J) 6,804

Answer 26

@quentinloy

Answer 27

Sorry, what's the question?

Answer 28

oh, I see it

Answer 29

so 11 is a multiple of 33, so you really need to know when it will when event A and event C will coincide, but cause whenever C occurs, so does B. So event C occurs in 33, 66, 99, 132 years. A does not occur in 33, 66, or 99, but it does occur in 132. 4x33=132. 1950+132 years is when all three events will occur at the same time