Tan ^2x + 3 tanx + 1

Question

kira_yamato · Answer

So what's the question?

anonymous · Answer

Solve the equation in the interval [0, 2pi) using the quadratic equation

anonymous · Answer

let u = tanx

u^2 + 3u + 1 = 0

solve for u using the quadratic equation. plug tanx = u back in.

let me know if this solves your problem or if i should proceed ^_^

anonymous · Answer

I got -3 +/-  square root 5 divided by 2

kira_yamato · Answer

attachment

kira_yamato · Answer

D = 3^2 - 4(1)(1) = 9 - 4 = 5

anonymous · Answer

Kira... I do not understand how you get it to equal  0.36468. I keep getting a negative. What am I doing wrong?

kira_yamato · Answer

For alpha 1 and alpha 2, you need to take tan inverse of the modulus of the value. Because this gives you the basic angle and from there, you manipulate the values. What you found was the argument.
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