Question

I Need Help on How to Change a Point-Slope Formula into Standard Form.

Answer 1

I know that this is pointe-slope form:\[y-y _{1}=m(x-x _{1})\]And I know that this is standard form:\[Ax+By=C\]

Answer 2

If you need an example, then how to make this into standard form.:\[y-3=\frac{ 1 }{ 2 }(x+6)\]

Answer 3

Hi @ganeshie8 !

Answer 4

hey :)

Answer 5

get rid of fractions first
multiply both sides wid 2

Answer 6

So I multiply the fraction (one over two) and the 3, or the y?

Answer 7

\(\large y-3=\frac{ 1 }{ 2 }(x+6) \)

multiply both sides wid 2

\(\large \color{red}{2 \times} (y-3) = \color{red}{2 \times} \frac{ 1 }{ 2 }(x+6) \)

Answer 8

we multiply 2 wid the entire thing,
both left side and right side

Answer 9

it cancels out on right side,
left side simply distribute

Answer 10

So...\[2y-6=1(x+6)\]Then...\[2y-6=1x+6\]Am I right?

Answer 11

Looks good !

Answer 12

next, subtract 2y both sides

Answer 13

we will move 2y to the right side and see

Answer 14

How do I subtract 2y (sorry)?

Answer 15

\(\large y-3=\frac{ 1 }{ 2 }(x+6) \)

multiply both sides wid 2

\(\large \color{red}{2 \times} (y-3) = \color{red}{2 \times} \frac{ 1 }{ 2 }(x+6) \)

\(\large 2y-6 = 1x + 6\)

subtract 2y both sides

\(\large -6 = 1x-2y + 6\)

Answer 16

we cant subtract it away as such,
so we simply write -2y on right side

u can see that, 2y and -2y killed each other on left side

Answer 17

\(\large y-3=\frac{ 1 }{ 2 }(x+6) \)

multiply both sides wid 2

\(\large \color{red}{2 \times} (y-3) = \color{red}{2 \times} \frac{ 1 }{ 2 }(x+6) \)

\(\large 2y-6 = 1x + 6\)

subtract 2y both sides

\(\large -6 = 1x-2y + 6\)

subtract 6 both sides

\(\large -12 = 1x-2y\)

this is same as,

\(\large 1x-2y = -12\)

Answer 18

thats the complete solution,
see if it makes some sense... :)

Answer 19

It seems like it makes sense. Are there specific steps like in general with no example?

Answer 20

there is oly one thing to remember :-
1) watever u do, do it to both sides

Answer 21

do one more problem, u wil feel confident im sure.
dont look for specific steps..... these are baby problems.... practicing is easier, than looking for specific steps.... :)

Answer 22

in the first step,
we multiplied both sides wid 2, ONLY BECOZ, we saw that 1/2 is there on right side

Answer 23

Okay. I have more of those equations to come.

Answer 24

if it was not a fraction, we wud have done something else (which u wil get to know by practice i hope)

Answer 25

lets do one more

Answer 26

convert below to standard form

\(\large y+1=3(x-2)\)

Answer 27

Oops, sorry for not replying @ganeshie8 . I had to submit the test. I actually had a question. In the first one, did you mupltiply by two because two was the denominator? I am trying to do one in my test by myself that also has a fraction, but the fraction is three over four.

Answer 28

I thinked I solved your problem @ganeshie8 :-D

Answer 29

Yes :)
just get rid of denominator - simply multiply both sides wid four, cuz four is in the denominator

Answer 30

Okay, so here is for your example:\[y+1=3(x-2)\]I have to use the distributive property to take away the parenthesis:\[y+1=3x-6\]Now I have to move the y to the right side by subtracting it on both sides.\[1=3x-y-6\]Now I add 6 to both sides so the one in the right can cancel out:\[7=3x-y\]Now my answer. It can also be expressed as \[3x-y=7\]OR\[3x-1y=7\]

Answer 31

Now for my problem which I believe I got right.

\[y-4=\frac{ 3 }{ 4 }(x+8)\]\[4\times(y-4)=4\times \frac{ 3 }{ 4 }(x+8)\]\[4y-16=3(x+8)\]\[4y-16=3x+24\]\[-40=3x-4y\]\[3x-4y=-40\]

Answer 32

@ganeshie8