What is the solution of the system of equations?
im working on this one now
x=4 y=-1 z=-3
Is this what you needed? or did you need the explaination as well
How you got it?
@agent0smith
These are not quick to solve... let's use the first and third equations to start 3x + 2y + z = 7 3x + 2y + 3z = 1 Subtract the second from the first: 3x + 2y + z = 7 -(3x + 2y + 3z = 1) ____________________ -2z = 6 now you find z = -3.
3x + 2y + z = 7 --->(-4) 5x + 5y + 4z = 3 ------------- -12x - 8y - 4z = -28 (result of multiplying by -4) 5x + 5y + 4z = 3 --------------add - 7x - 3y = - 25 3x + 2y + z = 7 -->(-3) 3x + 2y + 3z = 1 ---------------- -9x - 6y - 3z = -21 (result of multiplying by -3) 3x + 2y + 3z = 1 -----------------add -6x - 4y = -20 -7x - 3y = -25 -->(-4) -6x - 4y = -20 -->(3) ---------------- 28x + 12y = 100 (result of multiplying by -4) -18x - 12y = -60 (result of multiplying by 3) -----------------add 10x = 40 x = 4 now sub 4 in for x -7x - 3y = -25 -7(4) - 3y = -25 -28 - 3y = -25 -3y = -25 + 28 -3y = 3 y = -1 now sub 4 in for x and -1 in for y 3x + 2y + 3z = 1 3(4) + 2(-1) + 3z = 1 12 - 2 + 3z = 1 10+ 3z = 1 3z = 1 - 10 3z = -9 z = -3 check... 5x + 5y + 4z = 3 5(4) + 5(-1) + 4(-3) = 3 20 - 5 - 12 = 3 15 - 12 = 3 3 = 3 (correct) x = 4, y = -1, and z = -3
So basically we just plug in a number into the equation to see if it comes out true? @texaschic101 and thank you so much for making it really clear.
to check it....you plug in the numbers that you found for x,y,and z into one of the original equations, and if it comes out equal, then you got it right. As for finding x,y,and z, that takes a little bit of time.
The actual solving of these equations is really tedious, as you can see from texaschic The last part was just checking them.
that explains it perfectly...tedious
Thank you, your a math genius !lol
btw @texaschic101 it might've been faster had you first solved for z as i did... that took like one line of work
true...I should have done that :)
@OtonoGold After getting z = -3 plug that into two of the other equations, then solve them for x and y
Oh Ok, thank you. ! very helpful
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