Question

32^x=2
solve for x

Answer 1

can you express 32 as the power of 2 ?
32 = 2^???

Answer 2

I do not understand logarthim

Answer 3

\(\Large \log a^b= b\log a\)
so,
\(\log 32^x =x \log 32\)
ok?

Answer 4

is there any other way of working it out like an equation other than using log

Answer 5

yes

Answer 6

32 =2^???

Answer 7

please could you teach me

Answer 8

can you factor 32 ?

Answer 9

k
it is 2^5

Answer 10

yes,
so,
\(\Large 32^x = (2^5)^x =2^{5x} \)
got this ?

Answer 11

s

Answer 12

ask if any doubts...

Answer 13

ok, so
we have \(\Large 2^{5x}=2^1\)
comparing the exponents, we get
5x =1
ok?

Answer 14

no, i do not understand

Answer 15

which part ?

Answer 16

how can you get 2^5x=2^1

Answer 17

from the question 32^x=2

and 32 = 2^5

so, 2^(5x) = 2^1

Answer 18

why would it be 2^1?

Answer 19

a=a^1
its same thing, its like multiplying a with itself once
4=4^1
-10 = -10^1
\(\Large ♥=♥^1\)

Answer 20

k

Answer 21

do u have to mention it or is it optional?

Answer 22

no need to mention :)

Answer 23

so how can 5x =1

Answer 24

because when \(\Large x^m=x^n, \implies m=n\)