Question

If you have 240.0 mL of water at 25.00 °C and add 100.0 mL of water at 95.00 °C, what is the final temperature of the mixture? Use 1.00 g/mL as the density of water.

Answer 1

heat gained + heat lost =0

Q = mass x specific heat x delta T

240mL x 1 g/mL = 240 g
100 mL x 1 g/mL = 100 g

240 x 4.18 ( T - 25) + 100 x 4.18 ( T - 95)=0

divide by 4.18 ( specific heat of water)

240 ( T - 25 ) + 100 ( T - 95)=0

240T-(240x25) + 100T-(100x25)=0

240T -6000 + 100T- 2500=0
240T+100T=6000+2500
340T=8500
T=8500/340
T=25C

Answer 2

Thank you so much!

Answer 3

your welcome!!