Question

If the radius of a melting snowball decreases
at a rate of 1 ins/min, find the rate at which
the volume is decreasing when the snowball
has diameter 4 inches.

Answer 1

$$
V=(4/3 )\pi r^3\\
\cfrac{dV}{dt}=(4/3 )\pi 3r^2\times \cfrac{dr}{dt}\\
$$
$$
\cfrac{dr}{dt}=-\cfrac{1'}{min}
$$
So
$$
\cfrac{dV}{dt}=-(4/3 )\pi 3(4/2)^2\times 1=?\\
$$
In cubic inches per min.

Answer 2

Inches, not feet:
$$
\cfrac{dr}{dt}=-\cfrac{1"}{min}
$$

Answer 3

The Sky >.> Smiles upon you

Answer 4

well thank you! @Skyz

Answer 5

:P I know I know nothing of the relevance to the question! But had to.