Chemistry
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OpenStudy (anonymous):
What is the molarity of solution prepared by mixing 5.85g of NaCl in distilled water to obtain a final volume of 250ml?
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OpenStudy (adamconner):
Molarity= moles of solute/liters of solution
OpenStudy (adamconner):
do you know how to go from grams to moles?
OpenStudy (anonymous):
yes ifind the grams for nacl first right?
OpenStudy (adamconner):
yes
OpenStudy (adamconner):
i mean you find the moles. you have the grams
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OpenStudy (anonymous):
k i got 49.5
OpenStudy (anonymous):
mol
OpenStudy (adamconner):
how did you get that? moles= grams/molar mass.
so you have 5.85g NaCl and the molar mass for NaCl=58.45
OpenStudy (anonymous):
ok i found sodium chloride and add it up and got 49.5 iadded their mass numbers
OpenStudy (adamconner):
the molar mass of NaCl is molar mass of Na + molar mass of Cl
so MM of Na=22.9 and Cl=35.35
22.9+35.45=58.35
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OpenStudy (anonymous):
ohhhhhhh i c what i did wrong i accidetly used nitrogen thats y
OpenStudy (adamconner):
oh my bad MM for Cl is 35.45
OpenStudy (anonymous):
k i got 58.5
OpenStudy (adamconner):
ooh yea that makes a lot of difference
OpenStudy (anonymous):
then is it 58.5/250?
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OpenStudy (adamconner):
no, you have 250ml so you need to change that to Liters
OpenStudy (adamconner):
so you would divide 250/1000
OpenStudy (anonymous):
oh how can i tell when i have to change it to litres if i have a question like this
OpenStudy (adamconner):
well the formula for molarity is molarity=Moles of solute/Liters
OpenStudy (adamconner):
in the question it gives you milliliters but in the equation you need liters
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OpenStudy (anonymous):
ohh ok i c
OpenStudy (adamconner):
so what would your equation look like now?
OpenStudy (anonymous):
58.5/0.25
OpenStudy (anonymous):
molarity of 234
OpenStudy (adamconner):
ooh my bad, we forgot to change to moles
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OpenStudy (adamconner):
to find moles you divide grams(given in question)/MM which is 58.35
so that way you will have 5.85/58.35
OpenStudy (anonymous):
=0.1002
OpenStudy (anonymous):
0.1
OpenStudy (adamconner):
yes
now you go back to the molarity question and plug that in
so you have molarity=.1002/.25
OpenStudy (anonymous):
0.4
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OpenStudy (adamconner):
yep you got it!
OpenStudy (anonymous):
thanks alot for your help greatly appreciated.r u familiar with stoi chemistry?
OpenStudy (adamconner):
my pleasure. kinda. i can try, jus post it in a different question so if i can't help then someone else might be able to
OpenStudy (anonymous):
k thanks alot
OpenStudy (adamconner):
your welcome