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Chemistry 17 Online
OpenStudy (anonymous):

What is the molarity of solution prepared by mixing 5.85g of NaCl in distilled water to obtain a final volume of 250ml?

OpenStudy (adamconner):

Molarity= moles of solute/liters of solution

OpenStudy (adamconner):

do you know how to go from grams to moles?

OpenStudy (anonymous):

yes ifind the grams for nacl first right?

OpenStudy (adamconner):

yes

OpenStudy (adamconner):

i mean you find the moles. you have the grams

OpenStudy (anonymous):

k i got 49.5

OpenStudy (anonymous):

mol

OpenStudy (adamconner):

how did you get that? moles= grams/molar mass. so you have 5.85g NaCl and the molar mass for NaCl=58.45

OpenStudy (anonymous):

ok i found sodium chloride and add it up and got 49.5 iadded their mass numbers

OpenStudy (adamconner):

the molar mass of NaCl is molar mass of Na + molar mass of Cl so MM of Na=22.9 and Cl=35.35 22.9+35.45=58.35

OpenStudy (anonymous):

ohhhhhhh i c what i did wrong i accidetly used nitrogen thats y

OpenStudy (adamconner):

oh my bad MM for Cl is 35.45

OpenStudy (anonymous):

k i got 58.5

OpenStudy (adamconner):

ooh yea that makes a lot of difference

OpenStudy (anonymous):

then is it 58.5/250?

OpenStudy (adamconner):

no, you have 250ml so you need to change that to Liters

OpenStudy (adamconner):

so you would divide 250/1000

OpenStudy (anonymous):

oh how can i tell when i have to change it to litres if i have a question like this

OpenStudy (adamconner):

well the formula for molarity is molarity=Moles of solute/Liters

OpenStudy (adamconner):

in the question it gives you milliliters but in the equation you need liters

OpenStudy (anonymous):

ohh ok i c

OpenStudy (adamconner):

so what would your equation look like now?

OpenStudy (anonymous):

58.5/0.25

OpenStudy (anonymous):

molarity of 234

OpenStudy (adamconner):

ooh my bad, we forgot to change to moles

OpenStudy (adamconner):

to find moles you divide grams(given in question)/MM which is 58.35 so that way you will have 5.85/58.35

OpenStudy (anonymous):

=0.1002

OpenStudy (anonymous):

0.1

OpenStudy (adamconner):

yes now you go back to the molarity question and plug that in so you have molarity=.1002/.25

OpenStudy (anonymous):

0.4

OpenStudy (adamconner):

yep you got it!

OpenStudy (anonymous):

thanks alot for your help greatly appreciated.r u familiar with stoi chemistry?

OpenStudy (adamconner):

my pleasure. kinda. i can try, jus post it in a different question so if i can't help then someone else might be able to

OpenStudy (anonymous):

k thanks alot

OpenStudy (adamconner):

your welcome

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