Question

Can someone please help me with this derivative? Im really close but am missing something...
d/dx (Tanh(3x))^1/2)

Answer 1

\[\frac{ d }{dx}=(\tan 3x)^{\frac{ 1 }{ 2}}\]

Is that it?

Answer 2

tanh...hyperbolic function.

Answer 3

OK, it's differentiated the same. So, using the chain rule, you'd do the outside first.
\[\frac{ 1 }{ 2 }(\tanh(3x))^{\frac{- 1 }{ 2 }}\]

Answer 4

Then the next layer in...\[\sec ^{2}(3x)\]

Answer 5

And finally the last layer in...
3.

When you put it all together you get
\[\frac{ 3 sech ^{2}3x}{2\sqrt{\tanh 3x} }\]

Answer 6

Got it thanks alot Becki!