8. During a very quick stop, a car decelerates at 7.00 m/s2 .
(a) What is the angular acceleration of its 0.280-m-radius tires,
assuming they do not slip on the pavement?
(b) How many revolutions do the tires make before coming to rest,
given their initial angular velocity is 95.0 rad/s ?
(c) How long does the car take to stop completely?
(d) What distance does the car travel in this time?
(e) What was the car’s initial velocity?
(f) Do the values obtained seem reasonable, considering that this stop
happens very quickly?

Question

8. During a very quick stop, a car decelerates at 7.00 m/s2 .
(a) What is the angular acceleration of its 0.280-m-radius tires,
assuming they do not slip on the pavement?
(b) How many revolutions do the tires make before coming to rest,
given their initial angular velocity is 95.0 rad/s ?
(c) How long does the car take to stop completely?
(d) What distance does the car travel in this time?
(e) What was the car’s initial velocity?
(f) Do the values obtained seem reasonable, considering that this stop
happens very quickly?

anonymous · Answer

use the relationship between accelerationa and angular acceleration where a=r*alpha so to find a multiply your given angular accel by the radius of the wheel.

anonymous · Answer

and that is assuming it doesn't slip, which you stated it doesn't
-goodluck

anonymous · Answer

sorry I didn't realize it had a part bcd, but I would answer part c first then part b, in which you would find the time by dividing (omegaf-omegai)/alpha=time, then use the equation deltatheta=omegai*t^2 -(.5*alpha*t^2)