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Mathematics 21 Online
OpenStudy (anonymous):

help me find the soulution

OpenStudy (anonymous):

|dw:1383061689349:dw|

OpenStudy (anonymous):

\[\frac{ 2x-1 }{3 }+3\le-4\] So if you focus on the left side first how do you add a number to a fraction?

OpenStudy (anonymous):

well wouldn't you use inverse on the 3 and subtract it from -4?

OpenStudy (anonymous):

you could do that too, guess that is simpler :) so if you did that now you have: \[\frac{ 2x-1 }{3 }\le-7\]

OpenStudy (anonymous):

how would you get the 3 off the bottom?

OpenStudy (anonymous):

that is what im having problems with would you divide 3 from -7 or?

OpenStudy (anonymous):

or I mean multiply

OpenStudy (anonymous):

you actually multiply both sides so it would look like this: \[3* \frac{ 2x-1 }{ 3 }\le-7*3\]

OpenStudy (anonymous):

yeah you are on the right track so what is -7*3?

OpenStudy (anonymous):

-21

OpenStudy (anonymous):

would the answer be x=10?

OpenStudy (anonymous):

also could you possibly help me with another?

OpenStudy (anonymous):

don't forget your \[\le \] and the negative as well

OpenStudy (anonymous):

oh yeah thanks xD|dw:1383062384113:dw|

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