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Integral cosz dz/(z (z-2) (z-4)) at |z|=1
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\[\Large \oint\limits_\gamma^{}\frac{\cos(z)}{z(z-1)(z-4)}dz\qquad \gamma = \{z \ \ | \ \ |z|=1\}\]
Looks daunting? :D
@rrakes Stay with me ^_^
i need solution and the concept to solve.
Gladly. First, Cauchy-Goursat theorem. This integrand is analytic everywhere except for a few points known as poles. Can you identify the poles?
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yes 0 2 4
2? I don't think so :)
z-2 is there in denominator and at z=2 the integrand is not defined
There is no z-2 in your post -_- No matter: Is this the correct integral: \[\Large \oint\limits_\gamma^{}\frac{\cos(z)}{z(z-2)(z-4)}dz\]
@rrakes This is kind of important ^_^
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yes
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