Question

Express the derivative as a function of x alone.
Derivative at listed in comments.

Answer 1

\[y'=\frac{ 6x^2-y-1 }{ x }\]

Answer 2

don't get what you mean

Answer 3

It is a 3 part problem, c is "Confirm that the two results are consistent by expressing the derivative in part (a) as a function of x alone."

For part (a), the derivative is the y prime i stated in the comment.

Answer 4

Do you mean to take the partial derivative?

Answer 5

Sorry, I don't exactly understand what you mean by expressing it as a function of x alone.

Answer 6

shoot the original problem , please

Answer 7

Ok,
\[1) x+xy-2x^3=2\]
a)Find dy/dx by differentiating implicitly.
b)Solve the equation for y as a function of x, and find dy/dx from that equation.
c)Confirm that the two results are consistent by expressing the derivative in part (a) as a function of x alone.

Answer 8

a)? show me your work, please

Answer 9

\[1+y+y'x-6x^2=0\]
\[y'=\frac{ 6x^2-y-1 }{ x }\]

Answer 10

b?

Answer 11

\[y=\frac{ -x+2x^3+2 }{ x }\]

Answer 12

Ah, I see what you mean now. I'll let Loser66 help on this one, though.

Answer 13

\[y'=\frac{ 4x^3-2 }{ x^2 }\]

Answer 14

@bloopman I am not good at explanation, you help her, please

Answer 15

@asapthe for a, you still have y in y' right? replace that y = ... from original function, then, simplify it , you will see both a, b are the same.

Answer 16

got me?

Answer 17

You have it right, Loser66.

Answer 18

what do you mean y in y'?