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An Arc length 3 feet is cut off by a central angle of pi/4 raidians, find the area of the sector formed
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Could you help me please?
Probably not the quickest solution, but: since the arc is cut off by an angle of pi/4, it means it's 1/8th of the whole circle. It means the whole circle measures 3*8 = 24 = 2pi*R , where R is the radius of said circle, which measures 24/2pi. The surface of the whole circle is pi*R^2, replacing: \[\pi* ({24\over2\pi})^2 = 144\pi\]. Since you don't need the whole circle, but just 1/8th of it you get that your sector has a surface of 18pi.
So the final answer is 18 pi?
Apparently :) double check calculations to be sure, but the reasoning behind them works.
Thanks :)
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