Which of the following is a solution of 9x^2-5x = -3? (Quadratic formula)
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hartnn (hartnn):
\(9x^2-5x +3=0 \)
Compare this quadratic equation with \(ax^2+bx+c=0\)
find \[a=...?\\b=...?\\c=...?\\\] \[ \\ \sqrt{b^2-4ac}=...?\]
then the two roots of x are:
\(\huge{x_{1,2}=\frac{-b \pm \sqrt{b^2-4ac}}{2a}}\)
OpenStudy (anonymous):
wait that didn't help??
OpenStudy (anonymous):
i obviously know that
OpenStudy (anonymous):
but the answers have "i" in them so I'm confused
OpenStudy (anonymous):
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OpenStudy (anonymous):
@hartnn there's no point in just typing the quadratic formula. if i know i have to use it for the problem, i can just look it up. if ur not gonna help, then..
OpenStudy (anonymous):
I mean, like, i just don't need info I already have
hartnn (hartnn):
yes, first tell me what you get for b^2-4ac ?
OpenStudy (anonymous):
the choices are up there^^
hartnn (hartnn):
could you find a,b,c ?
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OpenStudy (anonymous):
hold on
OpenStudy (anonymous):
yeah ok, so a=9, b= -5, c= -3
OpenStudy (anonymous):
and what do you mean "the two roots of x"
OpenStudy (anonymous):
why does it say x 1,2 in front of the formula
hartnn (hartnn):
that there are 2 solutions for x
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hartnn (hartnn):
c is just +3
OpenStudy (anonymous):
ohh, i forgot to do the discriminant
OpenStudy (anonymous):
it is? why
OpenStudy (anonymous):
ohh i get it
OpenStudy (anonymous):
wait but i got a negative discriminant which means there are no real solutions...
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OpenStudy (anonymous):
how did u get a positive one
hartnn (hartnn):
for this, there are actually no real solutions,
thats why there is "i" in the answers
which is imaginary number
hartnn (hartnn):
so, what you got for b^2-4ac ?
OpenStudy (anonymous):
ohh
OpenStudy (anonymous):
i got -98
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OpenStudy (anonymous):
and negative means two imaginary solutions
hartnn (hartnn):
try again ?
OpenStudy (anonymous):
i did it wrong? ok
hartnn (hartnn):
25 -4*3*9 = ... ?
OpenStudy (anonymous):
ohhh i see my mistake hold on
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OpenStudy (anonymous):
wait ... its 567
hartnn (hartnn):
nopes, ist -83
OpenStudy (anonymous):
ugh i didnt do order of operations
OpenStudy (anonymous):
ok lets keep going
hartnn (hartnn):
so, you know
\(i =\sqrt {-1}\)
?
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OpenStudy (anonymous):
yeah
OpenStudy (anonymous):
oh so now we can look at the choices
hartnn (hartnn):
so, what about \(\sqrt{-83}\) ?
yes...
OpenStudy (anonymous):
OpenStudy (anonymous):
so sqrt -1 times -83
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OpenStudy (anonymous):
or is it 83
OpenStudy (anonymous):
i think its b
OpenStudy (anonymous):
bcuz the rest have a positive 5
OpenStudy (anonymous):
and for the b value it is negative 5
hartnn (hartnn):
-b means - (-5) = 5
so the answer should have +5
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OpenStudy (anonymous):
??
OpenStudy (anonymous):
but before we said it was negative
OpenStudy (anonymous):
can u like write it out??
OpenStudy (anonymous):
where did the negative sign before the (-5) come from
hartnn (hartnn):
yes
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