Question

what is lim x approach infinity lnx/square root of x ???

Answer 1

\[\lim_{x \rightarrow \infty} In \frac{x}{\sqrt x}\]
@khaled009 is this your problem?

Answer 2

\[\lim_{x \rightarrow \infty}\frac{ \ln x }{ \sqrt{x} }\]

Answer 3

@dpasingh

Answer 4

@Directrix

Answer 5

you can simplify \[\frac{x}{\sqrt{x}}\]right?

Answer 6

oh, my bad, it is natural logx/ sqrtx

Answer 7

you can put lnx into an exponential form, can't you?

Answer 8

Am I to understand that you actually tried your hand at a limit question?
You're rather... full of surprises, aren't you? :/

Answer 9

hey,
can you use l'hospital's rule ?

Answer 10

The question on everyone's mind XD

Answer 11

Is there even a way to find this without using L'Hôpital? XD

Answer 12

da squeeezeee

Answer 13

Okay, danny-boy... squeeze away, then XD

Answer 14

but really who knows the squeeze thm

Answer 15

That's L'Hôpital.
Until further notice, that will be considered... *cheating* @dan815
XD

Answer 16

then
squeeze
http://www.youtube.com/watch?v=iyTPDuh-LF8

Answer 17

\[\lim \frac{ lnx }{ \sqrt{x} } =\lim lnx \times \lim \frac{ 1 }{\sqrt{x} } =0\]

Answer 18

I know what squeeze is >:(

Answer 19

sry it should be zero

Answer 20

ikram u cannot do that

Answer 21

but it should be zero lohospitals way will give u that

Answer 22

Well, more power to you guys anyway, I just dropped by to check out the status quo LOL
Catch you guys later or something ^_^
---------------
Terence out

Answer 23

ok @dan815 mmm will i can do it ,but i'll simplify why i do it
\[\lim \frac{ \ln x }{ \sqrt{x} }=\lim \frac{ \ln \sqrt{x}^2 }{ \sqrt{x}}= 2\times \lim \frac{ \ln \sqrt{x} }{ \sqrt{x}}=2\times 0=0\]

Answer 24

ln1 is equal to 0, right?

Answer 25

aha but y ist matter in this one ??

Answer 26

I am not even close to this, I see that it is limited and what it is limited to, I kind of understand this, but I am not even in precalc yet.

Answer 27

well , u know that \[\lim \frac{ \ln x }{ x } =0\] when x apr to positive infinite try to simplify the qs using this rule , now
\[x=\sqrt{x} ^2\] ist clear now??

Answer 28

\[\lim_{x \rightarrow \infty}\frac{ \ln x }{ \sqrt{x} }\\=\lim_{x \rightarrow \infty}x^{-1/2}{ \ln x }\\=\lim_{x \rightarrow \infty}{ \ln x^{x^{-1/2}} }\]

Answer 29

I kind of get it the first time already, but your comment "y ist matter in this one" confused me, ikram002p.

Answer 30

u asked about if ln1 =0, i said yes it's but why u neede in this question so im curious , any way sry to confuse u :)

Answer 31

\[\lim_{x \rightarrow \infty} x^-(1/2)*lnx\]

Answer 32

\[\lim_{x \rightarrow \infty} \ln x^(1/\sqrt{x})\]