Question

int (1/x^2+x)dx

Answer 1

you can writ it like this:
int(x^-2)dx+int(x)dx=-1/x+(x^2)/2

Answer 2

is it
\(\large \int \dfrac{1}{x^2+x}dx\)
??

Answer 3

really???
i think that its: int(1/x^2)+int(x)
???

Answer 4

if its that, the you're correct :)
else you'll need partial fractions...

Answer 5

can you explain more about partial fraction?

Answer 6

yes,
for that we need to factor the denominator

Answer 7

\(\large \dfrac{1}{x(x+1)}=\dfrac{A}{x}+\dfrac{B}{x+1}\)
now you find A, B
know how to ?

Answer 8

yes
Ax+A+Bx=1
so
(A+B)x=0
A=1
so B=-1
1/x-1/x+1
?

Answer 9

absolutely correct!
good work :)
now those are easy to integrate.

Answer 10

thanks hartnn

Answer 11

welcome ^_^