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Find f(x) if f(2) = 2 and the tangent line at x has slope (x − 1)e^(x^2 − 2x)
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If f(x) is the function, then f'(x) is the slope of the tangent line at x. They have given you f'(x) = (x − 1)e^(x^2 − 2x) and are asking for f(x). Integrate and you will have f(x). The integration will introduce a constant which can be resolved by setting x = 2 and f(x) as 2 because they give you f(2) = 2.
so what would i do?
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