Let f (x) = 5x^2 + 7 and g(x) = x – 3. (a) Find the composite function ( f o g)(x) and simplify. Show work. (b) Find ( f o g ) (2) can anyone tell me if a.) =5x^3+7x-3 and if b.) =24? Thanks!
Mind telling me how you got your answer to (a) ?
f(g(x))= f(5x^2+7) x(5x^2+7)-3 5x^3+7x-3 maybe?
Let me walk you through it, aye?\[\Large f(\color{red}x)=5\color{red}x^2+7\]\[\Large g(\color{green}x) = \color{green}x-3\]
ok thanks
Now, \[\Large (f\circ g)(\color{blue}x) = f(\color{red}{g(x)})\]This, you know, right?
yes
So what I want you to do for now is replace all instances of \(\color{red}x\) in \(f(\color{red}x)\) with \(\color{red}{g(x)}\) Like so: \[\Large f(\color{red}x) =5\color{red}x^2+7\]\[\Large f(\color{red}{g(x)}) = \color{blue}?\]
well x-3 into 5x^2+7 right?
That is correct...
but I thought I did that, must have written it wrong
Then show me what you have written, let's see if we can pinpoint the error, if there is one.
x(5x^2+7)-3 wrong?
Yup. Take it slow... truth is it's far simpler than that. \[\Large f(\color{red}{g(x)}) = f(\color{red}{x-3})\]
5(x-3)^2+7
That's much better :) Simplify.
5(x^2-6x+9)+7?
Good so far... now distribute the 5 within the parentheses, and then simplify further.
5x^2-30x+52?
Bingo :) \[\Large (f\circ g)(\color{blue}x)=5\color{blue}x^2-30\color{blue}x+52\] That wasn't so bad, was it? Now find \[\Large (f\circ g)(\color{blue}2)\]
12?
wait never mind
Pardon?
thats not right
If it isn't, then correct it.
i think its 10
You think? But are you sure? (This is arithmetic, don't go wrong on me now XD )
\[\Large (f\circ g)(\color{blue}2) = 5(\color{blue}2)^2 - 30(\color{blue}2) + 52\]
ok i did have it right!
Yes you did... you had me worried there. Job (almost) well done :) Good luck with the rest XD (If any) signing off now... ------------------------------------------------- Terence out
THANK YOU!!!!!!!!!!!
@autumn_sky hope this helps
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