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find a function f(y) such that f(1+lnx)=x for all x>0
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f(y)=e^(y-1) then y=(1+lnx) and f(y)=f(1+lnx)=e^((1+lnx)-1)=e^lnx=x for all x>0
can you explain it? but thank you
I'll try to explain my reasoning. First I set 1+ln(x)=x, then I subtract the 1 from both side to form ln(x)=x-1. Next I raise both side as a power of e, obtaining e^ln(x)=e^(x-1). This simplifies to x=e^(x-1). All we need now is to change the variable x to y.
that makes sense thank you
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