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According to Descartes' rule of signs, how many possible positive real roots could the following polynomial function have? f(x)=3x^4-5x^3+5x^2+5x-2 A. 3 B. 3 or none C. 2 or 0 D. 4
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\[f(x) = +3x^4-5x^3+5x^2+5x-2\] there are three cases where the signs change from positive to negative or negative to positive.
so would it be B? because you do that thing where you subtract 2 from the number of sign changes?
group 1 : +3x^4 - 5x^3 group 2: -5x^3 + 5x^2 group 3 :+5x-2 so 3 signs in the positive case.
I think A. if you counted by two's it would be 3 and 1 .
it's 3 or 1 :)
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