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Mathematics 54 Online
OpenStudy (anonymous):

Help needed ASAP! Question below

OpenStudy (anonymous):

\[\frac{ 2x+1 }{3 }=\frac{ x+6 }{ 2 }\] Could someone show me step by step how to solve this?

OpenStudy (anonymous):

cross multiply first that gives you 2(2x+1) = 3(x+6)

OpenStudy (anonymous):

now distribute 4x+2 = 3x +18

OpenStudy (anonymous):

are you following...

OpenStudy (anonymous):

Yeah... I'm a bit confused on the cross multiplying

OpenStudy (anonymous):

ok lets go back, in order to get rid of the bottom for the left side lets multiply both sides by 3 3(2x+1)/3 = 3(x+6)/2 which reduces to 2x+1 = 3(x+6)/2

OpenStudy (anonymous):

now on the right side we want to get rid of 2 so lets multiply both sides by 2 2*(2x+1) = 2*3*(x+6)/2 but that reduces to 2*(2x+1) = 3*(x+6) since 3/3 and 2/2 reduces to 1

OpenStudy (anonymous):

cross multiplication is just a quicker way to do it and it always works

OpenStudy (anonymous):

so now we just distribute 2*(2x+1) = 3*(x+6) and gives 4x + 4 = 3x + 18

OpenStudy (anonymous):

4x + 2 = 3x +18 sorry typo

OpenStudy (anonymous):

Okay... So then we just do the regular solving of it? The whole, take 3x away from both sides, then take 2 away from both sides?

OpenStudy (anonymous):

yes

OpenStudy (anonymous):

So.. x=16?

OpenStudy (anonymous):

yes thats correct

OpenStudy (anonymous):

Awesome! Thank you!

OpenStudy (anonymous):

yea no problem :D

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