Question

Differentiate the functions. Assume C is a constant.
g(x)=3(7)^5

Answer 1

So 3(7)^5 is a constant by itself, so the derivative is 0. Perhaps you are looking to evaluate the derivative of a function 3x^5 at the point x=7?

Answer 2

Derivative is zero so :X

Answer 3

Well the answer in the book says g'(x)=0. I wasn't clear how it is 0?

Answer 4

Well you have no x value, so the derivative will always be zero

Answer 5

Oh, well perfect then. So @malibugranprix2000 remember the derivative of a function is just the slope right? You're calculating how much the function changes when you change x.

How much does 3(7)^5 change when you change x? Just try setting x=0 and then x=1. Does 3(7)^5 change at all when we change x by 1? Nope. How about if we change x by increasing it from x=0 to x=a billion billion kazillion?

Nope, no change. You could say, the change was... zero. So not very surprisingly, the derivative is 0.

Answer 6

^ Thats a perfect explanation.

Answer 7

I was going to say, attempt to do power rule:)

Answer 8

or any rule for that matter, you have no x so :P

Answer 9

@Lukecrayonz Yeah, that's another great thing to try, if you know that you can multiply anything by 1 and it doesn't change and that anything to the 0 power is 1, then we can multiply that thing by x^0 and when we take the derivative, we are multiplying the whole thing by 0 by doing the power rule.

Answer 10

This makes sense now thanks @Kainui and @Lukecrayonz.

Answer 11

=D