simplify b^2-5b+25

Question

simplify b^2-5b+25

anonymous · Answer

@amistre64 could you solve this
simplify b^2-5b+25

amistre64 · Answer

im not sure what it means by "simplify" .. does it mean factor?

amistre64 · Answer

it looks complex to me ... 25-4(25) is a negative under the sqrt ..

anonymous · Answer

am,example
(x+2)(x+2)=
x^2+4x+4

amistre64 · Answer

(x+5)(x+5) = x^2 + 10x + 25

(x-5)(x-5) = x^2 - 10x + 25

(x+5)(x-5) = x^2 - 25

none of those fit

amistre64 · Answer

b^2-5b+25

b = 5 +-sqrt(25-4(25))
       -----------------
                       2


b = 5 +- 5 sqrt(-3)
       -------------
               2

anonymous · Answer

are you sure?

amistre64 · Answer

im pretty sure i remember how to do a quadratic formula

anonymous · Answer

can you explain how you got to the answer?

anonymous · Answer

@amistre64

anonymous · Answer

can you explain how you got to the answer?

amistre64 · Answer

i used the quadratic formula to define the roots of the equation with

amistre64 · Answer

we could also try completing the square .... which is just the longhand proof of the quad formula

amistre64 · Answer

b^2-5b+25 = 0

b^2-5b = - 25

b^2-5b + 25/4 = - 25 + 25/4

(b-5/2)^2 =  -75/4

b-5/2 =  +- sqrt(-75)/2

b = 5/2 +- sqrt(-75)/2