I NEED HELP : ? Medal And Fan
1. A line segment on a number line has its endpoints at –9 and 6. Find the coordinate of the midpoint of the segment. (1 point) 1.5 –1.5 2 –3 2. Find the coordinates of the midpoint of given that H(–1,3) and X(7,–1). (1 point) (3, 1) (0, 4) (–3, 1) (–4, 0) 3. Find the distance between the points R(0,5) and S(12,3). Round the answer to the nearest tenth. (1 point) 10.4 16 12.2 11.8 4. An airplane at T(80,20) needs to fly to both U(20,60) and V(110,85). What is the shortest possible distance for the trip? (1 point) 165 units 170 units 97 units 169 units
excuse me srry but please post one question at a time if you have more questions just make a new question
If you werent going to help what was the point of posting that ? Its not like you were helping. #Dont post unnecessary things . Thats annoying thanks.
Love Your Picc BTW : )
@Jadeishere
For problem 1, you need to find the midpoint. I would suggest that you add the two numbers together and then divide by two. Try that and see what you get.
-1.5 ?
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-1.5 is what I got.
For problem 2, use this formula. \(\displaystyle midpoint=(\frac{x_1+x_2}{2},\frac{y_1+y_2}{2})\)
Do you know how to use this formula?
Lol, that's like the same for finding slope, almost, in equations =)
Similar, but not quite :P
I know, I'm just saying its almost the same
awhh man ya lost me__- lmfaoo
Sorry, I went off on a tangent. I will delete the slope one.
You guys makin me feel sooooo Dumb . Im a Senior but I never paid attention in class and now im like stuck
Let's look at this again, \(\displaystyle midpoint=(\frac{x_1+x_2}{2},\frac{y_1+y_2}{2})\) We have two points given for the problem. \(H(–1,3)\longrightarrow H(x_1,y_1)\) \(X(7,–1)\longrightarrow X(x_2,y_2)\) Does this make more sense?
Okay, these questions are worth anything its a quick check. Can you give me the answers and show me all your steps as to how you got the answers cause im gonna have homework tonight I need to get this down. Okay so whats the next step
You just take those points and plug them into the formula. It should be really easy. -1+7 divided by 2 3+-1 divided by 2 Easy peasy :)
Oh wow so the answer would be 3, 1
In coordinate form of course :)
Okay :D whats next
Problem 3 I suppose, do you think you could solve it if I gave you the formula?
Ill give it a try
\(d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}\) Think you got this?
Oh my WTF is that ! lol
That is the distance formula :P You find the two different x and y values just like we did in the problem above.
Hold on im gonna try
, 12 <--- THOSE ARE X AND THESE ARE Y ------> 5, 3 RIGHT?
0, 12 **
Indeed :)
Now im stuck ... lol
12-0..... squared...... 3-5....... squared...... squareroot of all of that.
0 and 2.23 ?
12-0=12 square that, 144 3-5=-2 square that, 4 add them together, 144+4= 148 what is the square root of 148?
12.16 ?
Does that round to one of the answers? :)
would it b 12.2 ?
Indeed :D
Yayyyyyy one more one more ! lol
Ok, this last one you will need the distance formula for it. You need to find which is the shortest distance between points. "4. An airplane at T(80,20) needs to fly to both U(20,60) and V(110,85). What is the shortest possible distance for the trip?" The distance from point T to U plus the distance from U to V OR The distance from T to V plus the distance from V to U Make sense?
can you do it ? For me lol too much math in one day lmfaoo
lets go with 165
WOOP WOOP . Thank you . Can you help with more later on ?
perhaps, I am kinda tired and need to write some code. If it isn't quite as long as this one, sure :P
Wow, helped you for over an hour :D
I know thank you and I sent you something pm
Did you get my message
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