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Mathematics 27 Online
OpenStudy (jacobbirddog):

ill fan and medal Which of the ordered pairs in the form (x, y) is a solution of this equation? http://static.k12.com/bank_packages/files/media/mathml_355b5808c2c83f7ebd7c6388393b6eba49d4b9db_1.gif A. Neither is a solution. B. Both are solutions. C. The first is a solution, but the second is not. D. The first is not a solution, but the second is.

OpenStudy (anonymous):

6x-y/2=14 (-9, 3) (2, -4) What is the first step?

OpenStudy (anonymous):

Do you know which numbers replace what?

OpenStudy (anonymous):

(x, y)

OpenStudy (anonymous):

You have two equations you have solve: \[6\times-9-\frac{ 3 }{ 2 }\] = 14 \[6\times2-\frac{ -4 }{ 2 } = 14\]

OpenStudy (anonymous):

Hello?

OpenStudy (jacobbirddog):

sorry i was afk

OpenStudy (anonymous):

Do you know how to put the numbers into the equation?

OpenStudy (jacobbirddog):

no

OpenStudy (anonymous):

They are ordered so, (X, Y) You put the X and Y into the equation

OpenStudy (anonymous):

The asnwer is D

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