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Mathematics 12 Online
OpenStudy (anonymous):

evaluate the integral

OpenStudy (anonymous):

OpenStudy (anonymous):

try wolfram

OpenStudy (anonymous):

12/5 x^(5/2) [25,81]

OpenStudy (yttrium):

Yeah. I think tonks method is accepetable.

OpenStudy (anonymous):

Im not sure what you did :/

OpenStudy (yttrium):

You can just input x inside the sqrt sign. making it integral of 6x^3/2

OpenStudy (anonymous):

much lower than what you had, elaornelas

OpenStudy (anonymous):

x = √x^2 x*√x = x^3/2

OpenStudy (yttrium):

\[6\int\limits_{81}^{25} x ^{\frac{ 3 }{ 2 }}dx\]

OpenStudy (anonymous):

hm I'm sorry I'm still kind of confused :/

OpenStudy (anonymous):

i understand why you moved the 6, but not sure how to go about getting the solution from here

OpenStudy (yttrium):

\[6\frac{ x ^{\frac{ 5 }{ 2 }} }{ \frac{ 5 }{ 2 } }] (81.25)\]

OpenStudy (anonymous):

the integrand, 6x√x can be rewritten as 6x^(3/2) or 6x^1.5 then the power rule for anti-derivatives can be applied.

OpenStudy (yttrium):

Just apply algebra. We know that xsqrt(x) = x^1 (x)^1/2 --> adding their exponents will yield to x^(1+(1/2)) or x^(3/2) or simply sqrt(x^3)

OpenStudy (yttrium):

@elaornelas do you follow?

OpenStudy (anonymous):

so so!

OpenStudy (yttrium):

So what's next?

OpenStudy (anonymous):

ok well let me show you what i have written down

OpenStudy (anonymous):

\[-6\int\limits_{25}^{81}x(x)^{\frac{ 1 }{ 2 }}\]

OpenStudy (anonymous):

Treat the x like it has an exponent of one and add the exponents (same base) to make it one term.

OpenStudy (yttrium):

Why -6? Shouldn't be + And just simplify the expression \[x(x)^{\frac{ 1 }{ 2 }}\] this is actually same to \[x ^{\frac{ 3 }{ 2 }} = \sqrt{x ^{3}}\]

OpenStudy (anonymous):

negative is fine because she switched the bounds

OpenStudy (anonymous):

yes exactly @Tonks

OpenStudy (yttrium):

oops, sorry I didn't see that. my bad :D

OpenStudy (anonymous):

its fine! @Yttrium :)

OpenStudy (yttrium):

So you get it now, why it became sqrt(x^3)??

OpenStudy (anonymous):

@elaornelas do you get the x^(3/2) (same question)?

OpenStudy (anonymous):

yes i do @Tonks so would this mean my result would be \[\frac{ -12x ^{\frac{ 5 }{ 2 }} }{ 5 }\]???

OpenStudy (anonymous):

yes: -12/5 x^(5/2) [25,81]

OpenStudy (yttrium):

Yeah :D

OpenStudy (anonymous):

-12/5* 55924 blech!

OpenStudy (anonymous):

yay! @Tonks @Yttrium :) OK so NOW….. is this the correct setup -[F(b)-F(a)]=__?

OpenStudy (anonymous):

gotta go, good luck, you two!

OpenStudy (yttrium):

Owyeah :D

OpenStudy (anonymous):

ok well i got this real weird number :/ "134217.6"

OpenStudy (yttrium):

uh oh is that wrong?

OpenStudy (anonymous):

not sure :/ I'm confused @Yttrium

OpenStudy (anonymous):

\[\int\limits 6x \sqrt{x } dx=\frac{12 x^{5/2}}{5} \]\[\left(\frac{12\ 25^{5/2}}{5}\right)-\left(\frac{12\ 81^{5/2}}{5}\right)=-\frac{671088}{5} \]

OpenStudy (anonymous):

The fraction to 10 digits.\[N\left[-\frac{671088}{5},10\right]=-134217.6000 \]

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