Question

Need help with finding gradient of the tangent to the curve. Question attatched

Answer 1

So I got up to dy/dx = 2t-4/2e^0.5t

Answer 2

2(6)-4 = 8 but idk how to calculate 2e60.5t

Answer 3

2e^0.5t I mean

Answer 4

Mmmm it looks like you've gotten through most of it on your own.\[\Large 2e^{0.5t}, \quad t=6\qquad\to\qquad 2e^{3}\]Right? :o

Answer 5

so 2e^3 = 40.17

Answer 6

so 8/40.17 = 0.199

Answer 7

Yah I guess that works!
I would just leave it in exact form myself though :D\[\Large \frac{dy}{dx}(6)\quad=\quad 4e^{-3}\]

Answer 8

Oh ok thanks. Previously I calculated 2e^0.5(6) onto my calculater and i got 19.78

Answer 9

So thats why I got the final answer wrong

Answer 10

Thanks @zepdrix

Answer 11

oh cool :)