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Mathematics 30 Online
OpenStudy (anonymous):

A company that manufactures storage bins for grains made a drawing of a silo. The silo has a conical base, as shown below. What is the total volume of grains that can be stored in the silo? a. 34π ft3 b. 68π ft3 c. 136π ft3 d. 152π ft3

OpenStudy (anonymous):

OpenStudy (anonymous):

@Directrix ?

OpenStudy (solomonzelman):

I don't really get the shape, on the bottom is it |dw:1384314360692:dw|??

OpenStudy (solomonzelman):

OK, I see.

OpenStudy (solomonzelman):

First find the area of the circle on the top. \[A=πr^2\] since the diameter is 4, the radius is going to be 1/2 of that, which is 2. (I'll be posting small replies, so that you can follow me.)

OpenStudy (solomonzelman):

\[A=π2^2=4π\] to find the volume of the cylinder,

OpenStudy (solomonzelman):

\[4π \times 8 = 32π\] this is not it yet, we still need a small triangle.

OpenStudy (solomonzelman):

9.5-8 to find the length of the small triangle.

OpenStudy (solomonzelman):

So, \[4π \times 1.5 = 6π\]being that it is a triangle, divide by 2, so \[6π \div 2= 3π\] and add up the small triangle to the rest of the cylinder, \[32π+3π=35π\] I got 35π,

OpenStudy (solomonzelman):

@Easyaspi314 what is my mistake? I didn't get any of the choices

Directrix (directrix):

The silo is made up a right circular cylinder and a right circular cone. The volume of the cylinder = π*r²*h = π*2²*8 = 32π as computer earlier in the thread. To that, add the volume of the right circular cone. The volume of the cone is (1/3)*B*h where B is the area of the circular base and h is the height. V = (1/3) * π * (2)²*(1.5) = 2π @lowcard2 Add 32π to 2π to get the volume of the silo, cubic feet of course.

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