Question

i have 2x^2y/3n*2xn^2=4x^3/6n^3x is this correct

Answer 1

its multiplying fort his one

Answer 2

\[\huge \frac{2x^2 y }{3n }*2xn^2\] ?

Answer 3

yes

Answer 4

Then your answer isn't correct, it's missing a y for a start

Answer 5

\[\huge \frac{2x^2 y*2xn^2 }{3n } \]simplify this way.

Answer 6

oh, 4n^2x^3y

Answer 7

4n^2x^3y/6xn^3

Answer 8

4n^2x^3y isn't correct

Answer 9

oh i see i got 4n^3x^3y/3

Answer 10

Not right... what is n^2/n?

Answer 11

n

Answer 12

see your error?

Answer 13

yes

Answer 14

4x^3y/3

Answer 15

not quite... you already said n^2/n equals n, now you're missing an n\[\huge \frac{2x^2 y*2xn^2 }{3n }\]

Answer 16

4x^3yn/3

Answer 17

yes

Answer 18

thanks