Question

0

Answer 1

You find the vertical asymptotes by setting the denominator to zero

sin(x) = 0 -> gives you the values of x where the function will be discontinuous

Answer 2

can you explain that if possible, i really dont understand how to go about that

Answer 3

when is sin(x) zero? You dont know this?

You can graph the function:
https://www.desmos.com/calculator

Answer 4

-pi / pi

Answer 5

yes however those points are not in the range provided

Answer 6

so its just 0 then?

Answer 7

or we cant have 0 in the denominator so it cant be that, so (-π/2,0)∪(0,π/2) ?

Answer 8

[-pi/2,0) (0, pi/2] make sure you have [] for outside numbers