Question

When you graph a parabola with a vertical directrix and the directrix is x=-1/12y^2 and the form they give you is x=a(y-k)^2+h how do write x=-1/12y^2 to that format

Answer 1

you need the equation of parabola ?

Answer 2

yea like i know the format i just dont know what numbers to plug in my original equation is x=-1/12y^2

Answer 3

would it look like this x=3(y-0)+_?

Answer 4

it is in that format only,

x= (-1/12) (y-0)^2 +0

Answer 5

so,
here
a = -1/12
k=0
h=0

Answer 6

oh ok i understand now thanks

Answer 7

you're welcome ^_^