Question

y^2+3y=-x-2

Answer 1

graph and find vertex, focus, directrix

Answer 2

can we keep it as y^2+3y to find the y-coordinate in the parabola??

Answer 3

I believe we need to get the equation y^2+3y=-x-2 into vertex form.
do you remember the
y = a(x-h)^2 + k?

Answer 4

i suppose in our case it would be
x = a(y-k)^2 + h?

Answer 5

yes i do the equation would (y-k)^2=4a(x-h) right?

Answer 6

where do you get the 4 from?

Answer 7

y^2+3y=-x-2
becomes
x = -y^2 - 3y - 2

Answer 8

okay forget the 4
and yes i see that

Answer 9

how do i get the vertex now

Answer 10

can you complete the square for this:
x = -y^2 - 3y - 2

Answer 11

how did you 3/4

Answer 12

do you remember how to compete the square?