Question

Differentiate y= sec (x) / x ? Please help?

Answer 1

\[(\frac{f}{g})'=\frac{gf'-fg'}{g^2}\] with
\[f(x)=\sec(x), f'(x)=\sec(x)\tan(x), g(x)=x,g'(x)=1\]

Answer 2

thank you

Answer 3

@satellite73 Ok, I just realized I'm not sure if I can do this right.

Answer 4

would that make it ............ (1)(sec (x) tan(x)) - (sec (x) tan (x)) (1) / x^2

Answer 5

then the top becomes 0 and the answer is 0?