Question

Factor completely: 5ab + 3ay + 5b + 3y

Answer 1

\(\bf 5ab + 3ay + 5b + 3y\implies (5ab + 5b)+ (3ay + 3y)\quad \textit{common factors}\\ \quad \\
5b\color{blue}{(a+1)}+3y\color{blue}{(a+1)}\)

can you take more common factors there?

Answer 2

Thanks I get it :D finally! I matched my work up to this and figured it out (5b+3y)(a+1)

Answer 3

yw