Question

Find derivative, quotient rule:
(t+sec(t))/t^3

Answer 1

You could also just use the product rule .
(t+sec(t)) t^-3

Answer 2

\[g(t)=\frac{ t +sect }{ t^3 }\]

Answer 3

Do you know the quotient rule?

Answer 4

\[(\frac{ f }{ g })'(x)=(\frac{ f'(x)g(x)-f(x)g'(x) }{ g^2 (x) })\]

Answer 5

So what do you need help with exactly?

Answer 6

Setting it up, finding the derivative of a certain function?

Answer 7

Setting it up part I don't understand.

Answer 8

It's pretty much this:
\[\LARGE \frac{(t+sect)'(t^2)-(t+sect)(t^2)'}{(t^2)^2}\]

Answer 9

@Luigi0210 is that the first step?

Answer 10

Yup, now just differentiate and simply :)