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Mathematics 13 Online
OpenStudy (anonymous):

cos^6 x

OpenStudy (anonymous):

cos^2 x equals 1-sin^2x

OpenStudy (anonymous):

cos^6 x equals (cos^2 x)^3

OpenStudy (anonymous):

So it equals ( 1-sin^2 x)^3

OpenStudy (anonymous):

oh from there what would it be? because when i foil it out it I get stuck somewhere in the middle and my answer is always partly off from what it should be

OpenStudy (anonymous):

What should it be?

OpenStudy (anonymous):

You're going to have to foil it out

OpenStudy (anonymous):

Srry

OpenStudy (anonymous):

the book doesn't say on this one but for the previous questions like cos^4 x sin ^4 x im supposed to get 1/32(3/4 -cos4x+1/4cos8x) and I don't.. awk

OpenStudy (anonymous):

You should get -sin^6(x)+3 sin^4(x)-3 sin^2(x)+1

OpenStudy (anonymous):

oh in cos still tho

OpenStudy (anonymous):

We'll I think this is the answer

OpenStudy (anonymous):

Oh ok

OpenStudy (anonymous):

I think this is it then: 1/32 (15 cos(2 x)+6 cos(4 x)+cos(6 x)+10)

OpenStudy (anonymous):

ok ill try foiling again thanks :)

OpenStudy (anonymous):

I just converted everything back to cos using all the trig laws and stuff

OpenStudy (anonymous):

The answer is 1/32 (15 cos(2 x)+6 cos(4 x)+cos(6 x)+10)

OpenStudy (anonymous):

Geenggen!

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