Question

What is the derivative of: x^2/8 ?

Answer 1

\[\LARGE \frac{(8)(x^2)'-(8)'(x^2)}{(8)^2}\]
If you know the quotient rule, you should know this

Answer 2

16x/64 ?

Answer 3

No wait...

Answer 4

No, you're right, now simplify

Answer 5

(16x - x^2)/ 64 ?

Answer 6

Oh...

Answer 7

Remember, (8)'=0 and 0*x^2=0
So 16x-0= 16x/64 and 64 goes into 16 4 times, so x/4 if I'm not mistaken :)

Answer 8

Ahh yes! No variable = 0, when derived. Okay. I get it.... The neurons connected! :)
Thank you thank you thank you!!

Answer 9

No problem :)