Question

Help quick pleaseeeee!

Answer 1

start by finding y'

Answer 2

y'=6x^2+8x-5

Answer 3

Yes,
find the slope at x = 1

Answer 4

@ganeshie8 after you help this person with her question can you please help me with mine

Answer 5

sorry i suck at english :|

Answer 6

8?

Answer 7

y'(x) =6x^2+8x-5

slope at x = 1

y'(1) = 6(1)^2 + 8(1) - 5
= 6 + 8 -5
= 9

Answer 8

so what is the y intercept then

Answer 9

so
slope, m = 9
u knw a point (1, -2)

u can write teh equation of tangent in point slope form

Answer 10

y-1=9(x--2)
y-1=9(x+2)

Answer 11

nope, do it in ur regular way may be

Answer 12

y = mx + b

y = 9x + b

Answer 13

solve b, by putting (1, -2) above

Answer 14

-2=9*1+b
-2=9+b
-11=b

Answer 15

Yes, so the equation of tangent line at (1, -2) is :-

y = 9x - 11