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Mathematics 7 Online
OpenStudy (anonymous):

Concavity and Inflection (Medal to the winner. Comments...)

OpenStudy (anonymous):

OpenStudy (loser66):

I will give you medal if you show me how to solve this problem, XD

OpenStudy (anonymous):

That is why I posted it.

OpenStudy (agent0smith):

First find first and the second derivative.

OpenStudy (anonymous):

After I get the second?

OpenStudy (anonymous):

I know f''(x)=-12x^2-36x=0

OpenStudy (agent0smith):

Once you have the second, find where it's equal to zero, those are your points where it changes concavity

OpenStudy (anonymous):

But how do I denote that? X=-3 X=0

OpenStudy (agent0smith):

Now you have to find where it's concave up and down between those intervals. You could pick random points between them, and find f''

OpenStudy (agent0smith):

When f'' is positive = concave up f'' negative = concave down

OpenStudy (anonymous):

So I choose any number between -3 and 0?

OpenStudy (agent0smith):

And you want to check outside the interval. The function changes concavity twice.

OpenStudy (anonymous):

Alright, so if I chose -2 (f(x)=24) and 3 (f(x)=(-216) is that alright since one is negative and the other is positive?

OpenStudy (agent0smith):

Still need to check the other side of -3, though. But yes that tells you it's concave up where -3<x<0, and concave down x>0

OpenStudy (anonymous):

I'm sorry, how do I check the other side of -3?

OpenStudy (agent0smith):

The same way you checked the other side of 0 :P pick a number less than -3

OpenStudy (anonymous):

I'm sorry xD I'm running out of time with the problem and I don't understand how they want me to denote it in the end.

OpenStudy (agent0smith):

-3<x<0 is the same as (-3, 0). x>0 means (0, inf)

OpenStudy (anonymous):

I never knew that.

OpenStudy (anonymous):

How do I get inflection points then?

OpenStudy (agent0smith):

You already found them lol...

OpenStudy (agent0smith):

The first things you found!

OpenStudy (anonymous):

Oooooooooooookaaaaaaaaaay I seeeeee...so my final answer would be CU: (-3,0) CD: (0,inf) IP: (-3,0)? Sorry if I am getting this wrong, I'm learning this myself. My teacher hasn't been available and his substitute is less than accommodating :S

OpenStudy (anonymous):

Never mind, I see it is wrong with the last two ones.

OpenStudy (anonymous):

Alright, so I got CU, and IP (they wanted it without the parenthesis)...now to get that CD...thank you for your help thus far by the way...a lot.

OpenStudy (anonymous):

Alright, I picked -4 for the CD, and got -48.

OpenStudy (agent0smith):

CD is two intervals (-inf, -3) as well

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