2^x−4 +10 = 22
Please help!! this is urgent
Did you input the equation correctly?
\[2^{x-4}+10=22\] like that?
yes i did
Yeah @satellite73
subtract \(10\) from both sides to get \[2^{x-4}=12\]as a first step
then use the change of base formula to solve for \(x-4\) via \[x-4=\frac{\log(12)}{\log(2)}\]
and finally \[x=\frac{\log(12)}{\log(2)}+4\] and a calculator will give you a decimal approximation
But why do you do \[\log{2} \]
in the denominator?
Yes
you could always write \[x-4=\log_2(12)\] if you like, but unless you happen to know what \(\log_2(12)\) is, which i doubt, you need the change of base formula
so it would be 14.3?
that is you could write as your answer \[x=\log_2(12)+4\] but that doesn't really give you an answer
that is not what i get http://www.wolframalpha.com/input/?i=log%2812%29%2Flog%282%29+%2B4
yeah that wasnt a choice in my answers but thats what my calculator gave me. illl try again
thank you so much! @satellite73
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