Question

use the quadratic formula to find the zeros in the function. y-6=-2x^2

Answer 1

i don't get what you're saying @dalia_lam

Answer 2

Have you considered factoring?

\(2x^{2} + y - 6 = 0\)

Go!

Answer 3

How about solving
y = -2x° + 6

Answer 4

Oh, sorry. It says to use the quadratic formula. Do it!

a = 2
b = 1
c = -6

Answer 5

a = -2 b = 0 c = 6

x=-b +-sqrt(b²-4ac) / 2a

x = +-sqrt(-4*-2*6) / 2*-2

tkhunny - wouldn't b=0 and a =-2

Answer 6

continuing .........
x = sqrt(48) / -4
= 2 * sqrt(12) / -4
x = -sqrt (12)

Answer 7

thanks you so much!

Answer 8

Still working on it

Answer 9

x=4*sqrt(3)/-4
x = -sqrt(3)
and
x = sqrt(3)