Question

please help! (attached)

Answer 1

seen this question before

Answer 2

yes, but no one can help me with it :(

Answer 3

oh

Answer 4

( i posted it before)

Answer 5

try to isolate tan theta first.

Answer 6

so tan theta = 1/3 ?...

Answer 7

(theta is the 0 with the line across it right)?

Answer 8

@hartnn

Answer 9

this is theta \(\huge \theta \)

so to isolate tan theta, we subtract 1 from both sides, then divide sqrt 3 on both sides
and we have
\(\large \tan \theta = \dfrac{-1}{\sqrt 3}\)
got thill here ?

Answer 10

oh okay I took the square root and did -1^2.. sorry

Answer 11

yes

Answer 12

ok, so for which angles in 0 to 2pi , is the value of tan theta = -1/ sqrt 3 ??
can u find out ?

Answer 13

maybe from unit circle ?

Answer 14

umm its not o the unit circle I don't know how to get that :(

Answer 15

there is 1pi/3 = 60 degrees.. but

Answer 16

whats on the unit circle ?
sin and cos, right ??

tan is just sin/cos

so see for which angles, the ratio sin/cos gives you -1/sqrt 3

Answer 17

this right? .. what would 1pi/ sqrt of 3 be ?..

Answer 18

yes,
i'll give you one angle, you give me other

notice the angle \(\huge \dfrac{5 \pi }{6}\)

sin =1/2
cos = -sqrt 3/2
so tan = sin/cos = -1/sqrt 3

so one of the angles for which tan theta = -1/sqrt 3 is theta = 5pi/6

can you search for other angle ?

Answer 19

5pi/3 , 300 degrees

Answer 20

no.....5pi/3 gives you
sin = -sqrt 3/2
cos = 1/2
so, tan = -sqrt 3

Answer 21

but we need tan = -1/sqrt 3

Answer 22

so, 11pi/6

Answer 23

330 degrees

Answer 24

so the answers are ((5pi)/6) , and ((11pi)/6)

Answer 25

yes!

Answer 26

omg thank you soo much! I get it now :)

Answer 27

welcome ^_^