Question

a 10 kg object resting on a horizontal frictionless surface is subjected to two forces:F1=30N directed east and F2= 50N directed west. Find (a) its acceleration and (b) displacement after 10 seconds starting from rest.

Answer 1

a) F2-F1 = total force
= 20 N
F= ma
20=10a
a=.5 m/s^2

Answer 2

b) v =vo + at
v= 0 + .5*10
v= 5
v^2=vo^2+2ad
25 = 0 +2*.5*d
d = 25 m

Answer 3

how did you get .5 for a?

Answer 4

the 50 N to the right cancels out the 30 to the left leaving you with a total force of 20 to the right then newtons second law of F=ma gives you the acceleration

Answer 5

20/10=2

Answer 6

is it okey to use the formula S=Vot+1/2at^2 instead of v^2=vo^2+2ad

Answer 7

oh yeah i messed that up

Answer 8

but yes that equation will work in one step

Answer 9

both give you the right answer

Answer 10

so you mean tha accelaration would be 2 while s=100 m,is it right?

Answer 11

you got it

Answer 12

thank you so much!

Answer 13

no problem!