Question

PLEASE HELP me in algebra 2 lesson 8 unit 6

Answer 1

What r the questions??

Answer 2

what is the solution to the equation

Answer 3

2/13
1/12
-8/5
13/2

Answer 4

You must have written down the problem incorrectly, none of these are the correct answers.

Answer 5

it was suppose to be (-9x+5) sorry

Answer 6

Start out by squaring both sides, to extinguish the 1/2 (note: raising something to (1/n) is taking the nth root of that something; ie a^(1/2) means you're taking the square root of a)
$$-9x+5 = 3+4x $$

Now let's isolate x. We'll carry -9x over from the left, and add it to the right.
$$5 = 3+13x$$

Now carry +3 from the right, and subtract it from the left.
$$2 = 13x$$

Finally, divide the left side by 13
$$2/13 = x$$

Answer 7

ok thats what i got but i wasnt sure!


Let f(x) = –2x + 4 and g(x) = –6x – 7. Find f(x) – g(x). (2 points)

Answer 8

Alright, for this one, it's simple substitution.
$$[f(x) - g(x)] \to [(-2x + 4) - (-6x - 7)]$$

Distribute the negative into the right hand function, and now we can get rid of the parenthesis.
$$-2x + 4 + 6x + 7$$

And finally we have,
$$ 4x +11 $$

Answer 9

thank you for helping me!


What is the inverse of the given relation?
y = 3x + 12 (2 points)

Answer 10

Alright, for this one we want to solve for x.

We can firstly subtract 12 from both sides, which will give us what?

Answer 11

y-12=3x

Answer 12

Right.

Now we want to isolate x (just like I did in the first problem). How can we do that from here?

Answer 13

divide each by 3 and get y-4=x

Answer 14

so thats the answer?

Answer 15

Almost!

You need to divide the entire left side by 3.

So that it becomes

$$\frac{y-12}{3} = x$$

Answer 16

Now here comes the final step.

Simple swap x & y. Nothing special, just swap places.

$$ \frac{x-12}{3} = y $$

Answer 17

And that is your inverse of the given relation.

Answer 18

oh okay!