Question

What is the value of the normal force if the coefficient of kinetic friction is 0.22 and the kinetic frictional force is 40 newtons?

Answer 1

$$F_{f} = \mu \cdot F_{n}$$
$$40N = 0.22 \cdot F_{n}$$
$$\frac{40N}{0.22} = F_{n}$$
$$181.81 = F_{n}$$

Answer 2

181.81N